Hi, Jan-Ola!
25.12.2016
A late answere to dec. 20 mess. 651:
Jan-Ola Olsson (SWEDEN)JO_Olsson
5d
1
gasman
Just for reference: The Audi "Imbert" has only 5% upper hearth volume (cut cone) of the net gas consumption per second at WOT on motorways! (3500 RPM)
I’ve never done any calculations, but now that I do they suggest my gasifier is almost down to 2% ???
I did it this way:
1800/4×3500/60
That’s 26250 cm3/s.
(fault half the cylinder volume of gas, every other stroke, times rpm/60 fault).
That is so far one cylinder full filling/s, each stroke.
Divided by two for 4-stroke, and by two for 1:1 mixing
26250 cm3/s : 2 : 2 = 6562,5 cm3 net gas/s for one cylinder.
4 cyl. X 6562,5 cm3/s = 26250 cm3/s
Times a realistic filling factor 0,72 = 18900 cm3/s!!!
For all cylinders together…
Why not use the practical formula:
l X n X 3 = ??? Every stationary factor is there, you only
need to give the displacement and n = rpm:1000
…
My upper heart (nozzle tip to restriction) cut cone volume is 556 cm3.
556/26250 = 2.1%
What did I do wrong? What’s the proper way of calculating gas consumption?
…
556 cm3 : 18900 cm3 = 2,94179% ???
I still doubt that…
Have you used Conical frustum calculator?
(Observe they want radius, not diameter)